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m^2+36=-12m
We move all terms to the left:
m^2+36-(-12m)=0
We get rid of parentheses
m^2+12m+36=0
a = 1; b = 12; c = +36;
Δ = b2-4ac
Δ = 122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$m=\frac{-b}{2a}=\frac{-12}{2}=-6$
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